5.3.2. QP Modeling and Optimization in CΒΆ
In this chapter, we will use MindOpt C API to model and solve the problem in Example of Quadratic Programming.
Include the header file:
27#include "Mindopt.h"
Create an optimization model model
:
67 CHECK_RESULT(MDOemptyenv(&env));
68 CHECK_RESULT(MDOstartenv(env));
69 CHECK_RESULT(MDOnewmodel(env, &model, MODEL_NAME, 0, NULL, NULL, NULL, NULL, NULL));
Next, we set the optimization sense to minimization via MDOsetIntAttr()
and four variables are added by calling MDOaddvar()
. Their lower bounds, upper bounds, names, types and linear objective coefficients are defined as follows (for more details on how to use MDOsetIntAttr()
and MDOaddvar()
, please refer to Attributes):
74 /* Change to minimization problem. */
75 CHECK_RESULT(MDOsetintattr(model, MODEL_SENSE, MDO_MINIMIZE));
76
77 /* Add variables. */
78 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, 10.0, MDO_CONTINUOUS, "x0"));
79 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x1"));
80 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x2"));
81 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x3"));
Note
The non-zero elements of the matrix \(A\) will be inputted later. After adding the four aforementioned variables, certain parameters of the constraint matrix, specifically size
, indices
, and value
, are set to 0
, NULL
, and NULL
, respectively. This means that, as of now, model
has no constraints.
Now we set the constraint matrix \(A\) following the same procedure as in LP. The arrays row1_idx
and row2_idx
represent positions of the non-zero elements in the first and second rows while row1_val
and row2_val
represent corresponding values of the non-zero elements.
49 /* Linear part in the first constraint: 1 x0 + 1 x1 + 2 x2 + 3 x3 */
50 int row1_nnz = 4;
51 int row1_idx[] = { 0, 1, 2, 3 };
52 double row1_val[] = { 1.0, 1.0, 2.0, 3.0 };
53 /* Linear part in the second constraint: 1 x0 - 1 x2 + 6 x3 */
54 int row2_nnz = 3;
55 int row2_idx[] = { 0, 2, 3 };
56 double row2_val[] = { 1.0, -1.0, 6.0 };
We call MDOaddconstr()
to input the linear constraints into model
:
83 /* Add constraints.
84 * Note that the nonzero elements are inputted in a row-wise order here.
85 */
86 CHECK_RESULT(MDOaddconstr(model, row1_nnz, row1_idx, row1_val, MDO_GREATER_EQUAL, 1.0, "c0"));
87 CHECK_RESULT(MDOaddconstr(model, row2_nnz, row2_idx, row2_val, MDO_EQUAL, 1.0, "c1"));
Next, we will introduce the quadratic terms in the objective. Three arrays are utilized for this purpose. Specifically, qo_col1
, qo_col2
, and qo_values
record the row indices, column indices, and values of all the non-zero quadratic terms.
58 /* Quadratic part in objective: 1/2 [ x0^2 + x1^2 + x2^2 + x3^2 + x0 x1] */
59 int qo_nnz = 5;
60 int qo_col1[] = { 0, 1, 2, 3, 0 };
61 int qo_col2[] = { 0, 1, 2, 3, 1 };
62 double qo_values[] = { 0.5, 0.5, 0.5, 0.5, 0.5 };
We call MDOaddqpterms()
to set the quadratic terms of the objective.
89 /* Add quadratic objective term. */
90 CHECK_RESULT(MDOaddqpterms(model, qo_nnz, qo_col1, qo_col2, qo_values));
Once the model is constructed, we call MDOoptimize()
to solve the problem:
92 /*------------------------------------------------------------------*/
93 /* Step 3. Solve the problem and populate optimization result. */
94 /*------------------------------------------------------------------*/
95 /* Solve the problem. */
96 CHECK_RESULT(MDOoptimize(model));
We can retrieive the optimal objective value and solutions via getting attributes:
98 CHECK_RESULT(MDOgetintattr(model, STATUS, &status));
99 if (status == MDO_OPTIMAL)
100 {
101 CHECK_RESULT(MDOgetdblattr(model, OBJ_VAL, &obj));
102 printf("The optimal objective value is: %f\n", obj);
103 for (int i = 0; i < 4; ++i)
104 {
105 CHECK_RESULT(MDOgetdblattrelement(model, X, i, &x));
106 printf("x[%d] = %f\n", i, x);
107 }
108 }
109 else
110 {
111 printf("No feasible solution.\n");
112 }
Finally, we call MDOfreemodel()
and MDOfreeenv()
to free the model:
30#define RELEASE_MEMORY \
31 MDOfreemodel(model); \
32 MDOfreeenv(env);
117 RELEASE_MEMORY;
The complete example code is provided in MdoQoEx1.c:
1/**
2 * Description
3 * -----------
4 *
5 * Quadratic optimization (row-wise input).
6 *
7 * Formulation
8
9 * -----------
10 *
11 * Minimize
12 * obj: 1 x0 + 1 x1 + 1 x2 + 1 x3
13 * + 1/2 [ x0^2 + x1^2 + x2^2 + x3^2 + x0 x1]
14 * Subject To
15 * c0 : 1 x0 + 1 x1 + 2 x2 + 3 x3 >= 1
16 * c1 : 1 x0 - 1 x2 + 6 x3 = 1
17 * Bounds
18 * 0 <= x0 <= 10
19 * 0 <= x1
20 * 0 <= x2
21 * 0 <= x3
22 * End
23 */
24
25#include <stdio.h>
26#include <stdlib.h>
27#include "Mindopt.h"
28
29/* Macro to check the return code */
30#define RELEASE_MEMORY \
31 MDOfreemodel(model); \
32 MDOfreeenv(env);
33#define CHECK_RESULT(code) { int res = code; if (res != 0) { fprintf(stderr, "Bad code: %d\n", res); RELEASE_MEMORY; return (res); } }
34#define MODEL_NAME "QP_01"
35#define MODEL_SENSE "ModelSense"
36#define STATUS "Status"
37#define OBJ_VAL "ObjVal"
38#define X "X"
39
40int main(void)
41{
42 /* Variables. */
43 MDOenv *env;
44 MDOmodel *model;
45 double obj, x;
46 int status, i;
47
48 /* Model data. */
49 /* Linear part in the first constraint: 1 x0 + 1 x1 + 2 x2 + 3 x3 */
50 int row1_nnz = 4;
51 int row1_idx[] = { 0, 1, 2, 3 };
52 double row1_val[] = { 1.0, 1.0, 2.0, 3.0 };
53 /* Linear part in the second constraint: 1 x0 - 1 x2 + 6 x3 */
54 int row2_nnz = 3;
55 int row2_idx[] = { 0, 2, 3 };
56 double row2_val[] = { 1.0, -1.0, 6.0 };
57
58 /* Quadratic part in objective: 1/2 [ x0^2 + x1^2 + x2^2 + x3^2 + x0 x1] */
59 int qo_nnz = 5;
60 int qo_col1[] = { 0, 1, 2, 3, 0 };
61 int qo_col2[] = { 0, 1, 2, 3, 1 };
62 double qo_values[] = { 0.5, 0.5, 0.5, 0.5, 0.5 };
63
64 /*------------------------------------------------------------------*/
65 /* Step 1. Create environment and model. */
66 /*------------------------------------------------------------------*/
67 CHECK_RESULT(MDOemptyenv(&env));
68 CHECK_RESULT(MDOstartenv(env));
69 CHECK_RESULT(MDOnewmodel(env, &model, MODEL_NAME, 0, NULL, NULL, NULL, NULL, NULL));
70
71 /*------------------------------------------------------------------*/
72 /* Step 2. Input model. */
73 /*------------------------------------------------------------------*/
74 /* Change to minimization problem. */
75 CHECK_RESULT(MDOsetintattr(model, MODEL_SENSE, MDO_MINIMIZE));
76
77 /* Add variables. */
78 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, 10.0, MDO_CONTINUOUS, "x0"));
79 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x1"));
80 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x2"));
81 CHECK_RESULT(MDOaddvar(model, 0, NULL, NULL, 1.0, 0, MDO_INFINITY, MDO_CONTINUOUS, "x3"));
82
83 /* Add constraints.
84 * Note that the nonzero elements are inputted in a row-wise order here.
85 */
86 CHECK_RESULT(MDOaddconstr(model, row1_nnz, row1_idx, row1_val, MDO_GREATER_EQUAL, 1.0, "c0"));
87 CHECK_RESULT(MDOaddconstr(model, row2_nnz, row2_idx, row2_val, MDO_EQUAL, 1.0, "c1"));
88
89 /* Add quadratic objective term. */
90 CHECK_RESULT(MDOaddqpterms(model, qo_nnz, qo_col1, qo_col2, qo_values));
91
92 /*------------------------------------------------------------------*/
93 /* Step 3. Solve the problem and populate optimization result. */
94 /*------------------------------------------------------------------*/
95 /* Solve the problem. */
96 CHECK_RESULT(MDOoptimize(model));
97
98 CHECK_RESULT(MDOgetintattr(model, STATUS, &status));
99 if (status == MDO_OPTIMAL)
100 {
101 CHECK_RESULT(MDOgetdblattr(model, OBJ_VAL, &obj));
102 printf("The optimal objective value is: %f\n", obj);
103 for (int i = 0; i < 4; ++i)
104 {
105 CHECK_RESULT(MDOgetdblattrelement(model, X, i, &x));
106 printf("x[%d] = %f\n", i, x);
107 }
108 }
109 else
110 {
111 printf("No feasible solution.\n");
112 }
113
114 /*------------------------------------------------------------------*/
115 /* Step 4. Free the model. */
116 /*------------------------------------------------------------------*/
117 RELEASE_MEMORY;
118
119 return 0;
120}